The Gravitational Constant

In Cavendish's experiment

Explain the Cavendish's Experiment for the determination of $G$?

What is Cavendish experiment?

Cavendish Experiment to measure $G$ uses the concept of

Cavendish's experiment was performed in $1798$ i.e in ${18}^{\mathrm{th}}$ century.

In Cavendish experiment to determine the value of $\mathrm{G}$, name of apparatus used is _____ balance.

In Cavendish's experiment why lead ball was used?

Experimentally the value of universal gravitational constant $\left(\mathrm{G}\right)$ was measured by 

Cavendish experiment yields the value of acceleration due to gravity at the surface of the earth.

Define universal gravitational constant using newton's law of gravitation.

Value of the universal gravitational constant is $6.67\times {10}^{-n} \frac{\mathrm{N} {\mathrm{m}}^2}{{\mathrm{kg}}^2}$. Write the value of $n$.

Define universal gravitational constant. Write its SI unit.

The value of universal gravitational constant $G=6.67\times {10}^{-11} \mathrm{N}\mathrm{ }{\mathrm{m}}^2\mathrm{ }\mathrm{k}{\mathrm{g}}^{-2}$. The value of $G$ in units of ${\mathrm{g}}^{-1} \mathrm{c}{\mathrm{m}}^3\mathrm{ }{\mathrm{s}}^{-2}$ is $6.67\times {10}^{-n}$ . The value of $n$ is _____.

Find the value of $G$ from the following data: $M= 6\times {10}^{24} \mathrm{kg}, R=6400 \mathrm{km}, g= 9.774 \mathrm{m}/{\mathrm{s}}^2$

State SI unit and obtain dimensions of universal gravitational constant.